Question

An air capacitor is charged upto potential V₁. It is connected in to an identical uncharged capacitor filled with dielectric medium. After redistribution of charge if the potential difference of this combination is V then the dielectric constant of the substance will be-

• A. $\frac{V^{2}}{V_{1}–V}$
• B. V(V₁ – V)
• C. $\frac{V}{V_{1}–V}$
• D. $\frac{V_{1}–V}{V}$

Answer 1

Answer: (D)

$\frac{V_{1}–V}{V}$

Answer 2

` V = = Ž 1 + K =

\ K = $\frac { V _ { 1 } } { \mathrm {~V} }$ – 1 =