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Question: An air bubble of radius 5 mm rises through a vat of syrup at a steady rate. If the syrup has a densi...

An air bubble of radius 5 mm rises through a vat of syrup at a steady rate. If the syrup has a density of 1.4103 kg/m3 and its viscosity is 20 kg/m-s, the rate of rise of the bubble is

A

5.8 mm/s

B

4.2 mm/s

C

3.8 mm/s

D

3.2 mm/s

Answer

3.8 mm/s

Explanation

Solution

From equation, v = neglecting

density of air inside the bubble.

or, v = 2×(0.005)2×1.4×103×9.89×20\frac { 2 \times ( 0.005 ) ^ { 2 } \times 1.4 \times 10 ^ { 3 } \times 9.8 } { 9 \times 20 } = 3.8 mm/s