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Question: An air bubble in glass slab \(\left( {\mu = 1.5} \right)\) from one side is \(6\,cm\) and from the o...

An air bubble in glass slab (μ=1.5)\left( {\mu = 1.5} \right) from one side is 6cm6\,cm and from the other side is 4cm4\,cm. The thickness of glass slab is:
(A) 10cm10\,cm
(B) 6.67cm6.67\,cm
(C) 15cm15\,cm
(D) none of these

Explanation

Solution

The thickness of the slab is determined by using the refractive index formula. By using the apparent depth of the first side, the real depth is determined, for the apparent depth of the second side, the real depth is taken as the difference of the thickness and the real depth, then the thickness is determined.

Useful formula
The refractive index of the glass slab is given by,
μ=Real depthApparent depth\mu = \dfrac{{{\text{Real depth}}}}{{{\text{Apparent depth}}}}
Where, μ\mu is the refractive index of the glass slab.

Complete step by step solution
Given that,
The refractive index of the glass slab is, μ=1.5\mu = 1.5,
The apparent depth from first side is, 6cm6\,cm
The apparent depth from second side is, 4cm4\,cm
Assume that the real depth be xx, then
The refractive index of the glass slab is given by,
μ=Real depthApparent depth..................(1)\mu = \dfrac{{{\text{Real depth}}}}{{{\text{Apparent depth}}}}\,..................\left( 1 \right)
By substituting the real depth and apparent depth in the above equation (1), then the above equation (1) is written as,
μ=x6\mu = \dfrac{x}{6}
By substituting the refractive index value in the above equation, then the above equation is written as,
1.5=x61.5 = \dfrac{x}{6}
By rearranging the terms, then the above equation is written as,
x=1.5×6x = 1.5 \times 6
On multiplying the terms in the above equation, then
x=9x = 9
Now, using the refractive index formula for second side, then assume that the real depth is txt - x, then
μ=Real depthApparent depth\mu = \dfrac{{{\text{Real depth}}}}{{{\text{Apparent depth}}}}
By substituting the refractive index, real depth and apparent depth in the above equation, then
1.5=tx41.5 = \dfrac{{t - x}}{4}
Now substituting the value of xx in the above equation, then
1.5=t941.5 = \dfrac{{t - 9}}{4}
By rearranging the terms, then the above equation is written as,
t9=1.5×4t - 9 = 1.5 \times 4
On multiplying the terms in the above equation, then
t9=6t - 9 = 6
By keeping the term tt in one side, then
t=6+9t = 6 + 9
By adding the terms in the above equation, then
t=15cmt = 15\,cm

Hence, the option (C) is the correct answer.

Note: The refractive index is directly proportional to the real depth and the refractive index is inversely proportional to the apparent depth. As the refractive index increases when the real depth increases and the apparent depth decreases. As the refractive index decreases when the real depth decreases and the apparent depth increases.