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Question: An aeroplane moving horizontally with a speed of 720 km/h drops a food packet, while flying at a hei...

An aeroplane moving horizontally with a speed of 720 km/h drops a food packet, while flying at a height of 396.9 m. The time taken by a food packet to reach the ground and its horizontal range is (Take g = 9.8 m/sec2)

A

3 sec and 2000 m

B

5 sec and 500 m

C

8 sec and 1500 m

D

9 sec and 1800 m

Answer

9 sec and 1800 m

Explanation

Solution

Time of descent t=2hgt = \sqrt{\frac{2h}{g}} =2×396.99.8= \sqrt{\frac{2 \times 396.9}{9.8}}

t=9sect = 9sec

and horizontal distance S=u×tS = u \times t

S=(720×518)×9S = \left( \frac{720 \times 5}{18} \right) \times 9 =1800m= 1800m