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Question

Question: An aeroplane is moving with horizontal velocity \(u\) at height\(h\). The velocity of a packet dropp...

An aeroplane is moving with horizontal velocity uu at heighthh. The velocity of a packet dropped from it on the earth's surface will be (gg is acceleration due to gravity)

A

u2+2gh\sqrt{u^{2} + 2gh}

B

2gh\sqrt{2gh}

C

2gh2gh

D

u22gh\sqrt{u^{2} - 2gh}

Answer

u2+2gh\sqrt{u^{2} + 2gh}

Explanation

Solution

Horizontal velocity of dropped packet =u= u

Vertical velocity =2gh= \sqrt{2gh}

\therefore Resultant velocity at earth

=u2+2gh= \sqrt{u^{2} + 2gh}