Question

An aeroplane is moving with a velocity$u$. It drops a packet from a height $h$. The time $t$ taken by the packet in reaching the ground will be

• A. $\sqrt{\left( \frac{2g}{h} \right)}$
• B. $\sqrt{\left( \frac{2u}{g} \right)}$
• C. $\sqrt{\left( \frac{h}{2g} \right)}$
• D. $\sqrt{\left( \frac{2h}{g} \right)}$

Answer 1

Answer: (D)

$\sqrt{\left( \frac{2h}{g} \right)}$

Answer 2

The initial velocity of aeroplane is horizontal, then the vertical component of velocity of packet will be zero.

So $t = \sqrt{\frac{2h}{g}}$