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Question: An aeroplane is flying with a velocity U<sub>p</sub>. The plane takes in volume V of air of mass μ. ...

An aeroplane is flying with a velocity Up. The plane takes in volume V of air of mass μ. per second to burn mass m of fuel every second. The exhaust relative to plane has a speed of UE. b.h.p. of engine of the aeroplane is

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UP2(μ+m)UpUE(μm)746\frac { \mathrm { U } _ { \mathrm { P } } ^ { 2 } ( \mu + \mathrm { m } ) - \mathrm { U } _ { \mathrm { p } } \mathrm { U } _ { \mathrm { E } } ( \mu - \mathrm { m } ) } { 746 }

Answer

Explanation

Solution

The resultant force = forward thrust – backward thrust and forward thrust = UE × (μ + m)

Backward thrust = UP × μ

∴ Resultant thrust,

F = UE(μ + m) – UPμ

Power = F × v

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