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Question

Physics Question on projectile motion

An aeroplane is flying horizontally with a velocity of 216 km/h and at a height of 1960 m. When it is vertically above a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is (ignoring air resistance)

A

1200m

B

0.33 km

C

3.33km

D

33 km.

Answer

1200m

Explanation

Solution

: Horizontal velocity of aeroplane, u=216×100060×60=60m/su=\frac{216\times 1000}{60\times 60}=60\,m/s Time of flight, T=2sg=2×19609.8=20sT=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2\times 1960}{9.8}}=20\,s Horizontal range, =AB=nT=AB=nT =60×20=1200m=60\times 20=1200m .