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Question: An aeroplane is flying horizontally with a velocity of 600 km/h at a height of 1960 m. When it is ve...

An aeroplane is flying horizontally with a velocity of 600 km/h at a height of 1960 m. When it is vertically at a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is

A

1200 m

B

0.33 km

C

3.33 km

D

33 km

Answer

3.33 km

Explanation

Solution

Horizontal displacement of the bomb

AB = Horizontal velocity × time available

AB=u×2hg=600×518×2×19609.8=3.33Km.AB = u \times \sqrt{\frac{2h}{g}} = 600 \times \frac{5}{18} \times \sqrt{\frac{2 \times 1960}{9.8}} = 3.33Km.