Question

An aeroplane is flying at a height of 1960 m in horizontal direction with a velocity of 360 km/hr. When it is vertically above the point. A on the ground, it drops a bomb. The bomb strikes a point B on the ground, then the time taken by the bomb to reach the ground is

• A. $20\sqrt{2}$sec
• B. 20 sec
• C. $10\sqrt{2}$sec
• D. 10 sec

Answer 1

Answer: (B)

20 sec

Answer 2

$t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2 \times 1960}{9.8}}$= 20 sec