Question
Question: An Aeroplane flying horizontally at an altitude of \(490m\) with a speed of \(180kmph\) drops a bomb...
An Aeroplane flying horizontally at an altitude of 490m with a speed of 180kmph drops a bomb. The horizontal distance at which it hits the ground is
A). 500m
B). 1000m
C). 250m
D). 50m
Solution
Here, we understood the value of the bomb's horizontal altitude and velocity. So first, we cover the unit and measure the time to travel, then we find the distance to the ground by using the horizontal distance equation and the time is taken to determine the problem of that kind.
Formula used:
The velocity of time,
Motion of the object to taken time,
s=ut+21at2
s is the distance,u is the initial velocity. aacceleration and t time
Complete step-by-step solution:
Given by,
Speed of the airplane =180kmph
Here, the 180kmph=50m/sec
Its altitude =490m
First, we have to find the time to travel 490meter
Now,
The greater the release speed, the greater the distance covered in flight. This is because the larger the release of the projectile, the longer it will be in the air. The horizontal portion can work for longer on the projectile.
The given formula,
s=ut+21at2
Substituting the given value in above equation,
We get,
490=0×t+½×9.8×t2
On simplifying,
Here,
490=4.9t2
We rearranging the given equation,
We get,
490/4.9=t2
On solving the above equation,
100=t2
Again, we simplifying the equation,
10=t
Therefore,
Time taken to travel 490meter is equal to 10sec
Now,
We calculating the horizontal distance,
According to the formula,
horizontal distance=time taken×speed
We know that,
Distance =10×50
On simplifying,
We get,
Distance =500meter
Hence,
Thus, the option A is the correct answer.
Note: According to an angle is generated in the vertical plane by two connected lines i.e. between a low point and two higher points. Whenever a line is not horizontal. The slope could be downhill or uphill. Its steepness is dependent on the height difference between its points.