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Chemistry Question on Equilibrium

An acid HA ionises as HA⇌H++A−HA {\rightleftharpoons} H^{+} + A^{-} The pH of 1.0 M solution is 5. Its dissociation constant would be:

A

5

B

5?10−85 ? 10^{-8}

C

1?10−51 ? 10^{-5}

D

1?10−101 ? 10^{-10}

Answer

1?10−101 ? 10^{-10}

Explanation

Solution

Ka=[H+)2C−[H+),[H+]<<CK_{a} = \frac{[H^{+})^{2}}{C-[H^{+})}, \left[H^{+}\right] < < C =(10−5)21=10−10= \frac{\left(10^{-5}\right)^{2}}{1} = 10^{-10}