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Question: An AC voltage is applied to a resistance \(R\) and an inductor \(L\) in series. If \(R\) and the ind...

An AC voltage is applied to a resistance RR and an inductor LL in series. If RR and the inductive reactance are both equal to 3Ω3\,\Omega , the phase difference between the applied voltage and the current in the circuit is:
(A) π4\dfrac{\pi }{4}
(B) π6\dfrac{\pi }{6}
(C) π2\dfrac{\pi }{2}

Explanation

Solution

Hint The phase difference between the applied voltage and the current in the circuit is determined by using the phase difference formula, by using the given information in the formula, and taking the tan1{\tan ^{ - 1}} for the answer, the phase difference can be determined.
Useful formula
The phase difference between the applied voltage and the current in the circuit is given by,
tanϕ=XLR\tan \phi = \dfrac{{{X_L}}}{R}
Where, ϕ\phi is the phase difference between the applied voltage and the current, XL{X_L} is the inductive reactance of the inductor and RR is the applied resistance of the circuit.

Complete step by step solution
Given that,
The resistance of the circuit is, R=3ΩR = 3\,\Omega ,
The inductive reactance of the inductor is, XL=3Ω{X_L} = 3\,\Omega .
Now,
The phase difference between the applied voltage and the current in the circuit is given by,
tanϕ=XLR..................(1)\tan \phi = \dfrac{{{X_L}}}{R}\,..................\left( 1 \right)
By substituting the inductive reactance of the inductor and the resistance in the above equation (1), then the above equation (1) is written as,
tanϕ=33\tan \phi = \dfrac{3}{3}
By dividing the terms in the above equation, then the above equation is written as,
tanϕ=1\tan \phi = 1
By rearranging the terms in the above equation, then the above equation is written as,
ϕ=tan11\phi = {\tan ^{ - 1}}1
From the trigonometry, the value of the tan1(1)=45{\tan ^{ - 1}}\left( 1 \right) = {45^ \circ },
ϕ=45\phi = {45^ \circ }
Then the angle 45{45^ \circ } is equal to the π4\dfrac{\pi }{4}, then the above equation is written as,
ϕ=π4\phi = \dfrac{\pi }{4}
Thus, the above equation shows the phase difference between the applied voltage and the current in the circuit.

Hence, the option (A) is the correct answer.

Note In this problem we must know about the π\pi values for the different angles, in trigonometry there are different π\pi values for different angles. Here we use the angle 45{45^ \circ } and the π\pi value is π4\dfrac{\pi }{4}, like that for different angles different π\pi values are available.