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Question: An ac supply gives 30 V r.m.s. which passes through a 10 \(\Omega\) resistance. The power dissipate...

An ac supply gives 30 V r.m.s. which passes through a 10 Ω\Omega resistance. The power dissipated in it is.

A

902 W90 \sqrt { 2 } \mathrm {~W}

B

C

D

Answer

Explanation

Solution

P=Vrms2R=(30)210=90 WP = \frac { V _ { r m s } ^ { 2 } } { R } = \frac { ( 30 ) ^ { 2 } } { 10 } = 90 \mathrm {~W}