Question

An ac source of 200 V having angular frequency 100 rad/s is connected in the following circuit. Find current in the circuit.

graph TD A[AC Source 200V, 100 rad/s] --> L1(L1: 5H) L1 --> P P --> C(C: 200uF) P --> L2(L2: 0.5H) C --> R(R: 10 Ohm) L2 --> R R --> A

Answer 1

0 A

Answer 2

The capacitive reactance is $X_C = \frac{1}{\omega C} = \frac{1}{100 \times 200 \times 10^{-6}} = 50 \, \Omega$. The inductive reactance of $L_2$ is $X_{L2} = \omega L_2 = 100 \times 0.5 = 50 \, \Omega$. Since $X_C = X_{L2}$, the parallel combination of $C$ and $L_2$ is in resonance, resulting in infinite impedance. The total impedance of the circuit is therefore infinite, leading to a current of 0 A according to Ohm's law ($I = \frac{V}{Z_{total}}$).