Question

An ac source is of$\frac{200}{\sqrt{2}}\text{ V,50 Hz.}$ The value of voltage after$\frac{1}{\text{600}}\text{ s}$ from the start is

• A. 200 V
• B. $\frac{\text{200}}{\sqrt{2}}\text{ V}$
• C. 100 V
• D. 50 V

Answer 1

Answer: (C)

100 V

Answer 2

: $V_{rms} = \frac{200}{\sqrt{2}}V$

$V_{0} = \sqrt{2}V_{rms} = \sqrt{2} \times \frac{200}{\sqrt{2}} = 200VV = V_{0}\sin 2\pi\upsilon t = 200\sin\left( 2\pi \times 50 \times \frac{1}{600} \right) = 200\sin\frac{\pi}{6} = 200 \times \frac{1}{2} = 100V$