Question

An a-particle of mass 6.4 × 10^–27 kg and charge 3.2 × 10^–19 C is situated in a uniform electric field of 1.6 × 10⁵Vm^–1. The velocity of the particle at the end of 2 × 10^–2 m path when it starts from rest is-

• A. 2$\sqrt{3}$× 10⁵ms^–1
• B. 8 × 10⁵ms^–1
• C. 16 × 10⁵ms^–1
• D. 4$\sqrt{2}$ × 10⁵ms^–1

Answer 1

Answer: (D)

4$\sqrt{2}$ × 10⁵ms^–1

Answer 2

a = $\frac { \mathrm { f } } { \mathrm { m } }$ = = = $\frac { 2 \mathrm { eE } } { 4 \mathrm {~m} _ { \mathrm { p } } }$ =

u = 0 \ v² = u² + 2as v = $\sqrt { 2 \mathrm { as } }$