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Question: An a-particle of 10 MeV collides head-on with a copper nucleus (Z = 29) and is deflected back. Then ...

An a-particle of 10 MeV collides head-on with a copper nucleus (Z = 29) and is deflected back. Then the minimum distance of approach between the centres of the two is –

A

8.4 × 10–15 cm

B

8.4 × 10–15 m

C

4.2 × 10–15 m

D

None of these

Answer

8.4 × 10–15 m

Explanation

Solution

r = kq1q2ε\frac{kq_{1}q_{2}}{\varepsilon}