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Question

Mathematics Question on Sequence and series

An A.P., a G.P. and a H.P. have the same first and last terms and the same odd numbers of terms, the middle terms of the three series are in

A

A.P.

B

G.P.

C

H.P.

D

none of these.

Answer

G.P.

Explanation

Solution

Let aa and bb be the same first and last terms of the three series, each having (2n+1)\left(2n + 1\right) terms (i.e., odd number of terms). Then the middle term of the A.PA.P. is a+b2(=A) \frac{a+b}{2} \left(=A\right). the middle term of the G.PG.P. is ab\sqrt{ab}(i.e., GG). The middle term of the H.PH. P. is 2aba+b\frac{2ab}{a+b} (i.e., HH). Since A,G,HA, G, H are in G.PG.P. \therefore the middle terms of the three series are in G.PG. P.