Question
Question: An \(8\mu F\) capacitor is connected to the terminals of A.C. source whose \({V_{rms}}\) is 150 volt...
An 8μF capacitor is connected to the terminals of A.C. source whose Vrms is 150 volt and the frequency is 60Hz, the capacitive resistance is :
A) 0⋅332×103Ω
B) 2⋅08×103Ω
C) 4⋅16×103Ω
D) 12⋅5×103Ω
Solution
In a circuit if the inductor is connected then the inductor also supplies some resistance to the flow of the current and also if the capacitor is applied then the capacitor will not only do the storing of charge but contribute to the resistance of the circuit.
Formula used: The resistance offered by the capacitor is given by,XC=ωC1 where C is the capacitance and ω is the angular frequency. The formula of the angular frequency is given by ω=2πf where ω is the angular frequency and f is the frequency of the circuit.
Complete step by step answer:
It is given that the circuit has a capacitor of capacitance 8μF and the Vrms is 150 volts. Also the frequency of the circuit is 60Hz.
The angular frequency is given by,
⇒ω=2πf
Where f is the frequency.
Put the value of frequency f equal to 60Hz as given in the problem.
⇒ω=2π⋅(60)
⇒ω=120π………eq. (1)
The capacitive resistance is given by,
XC=ωC1
Where C is the capacitance and ω is the angular frequency.
⇒XC=ωC1………eq. (2)
Replace the value of angular frequency and capacitance from equation (1) into equation (2).⇒XC=120π×0⋅8×10−31
⇒XC=0⋅332×103Ω
The capacitive resistance is equal to XC=0⋅332×103Ω.
The correct answer for this problem is option A.
Note: The resistance offered by the inductor and by the capacitor will depend upon the angular frequency of the a.c. source the resistance offered by the capacitor in dc source is infinite as the angular frequency is zero. When an inductor is applied in a circuit with dc source then the resistance is zero as the angular frequency is zero of the circuit.