Question

An 8 kg block of ice, released from rest at the top of a 1.5 m long smooth ramp, slides down and falls with a velocity 2.5 ms^-1. Find angle of the ramp with horizontal.

• A. 12⁰
• B. 18⁰
• C. 15⁰
• D. 30⁰

Answer 1

Answer: (A)

12⁰

Answer 2

v² = (2g sin θ)s

or sin θ = $\frac { v ^ { 2 } } { 2 g s } = \frac { 2.5 \times 2.5 } { 2 \times 10 \times 1.5 } = \frac { 0.5 } { 2.4 } = 0.20$ or θ = 12⁰.