Question

An 8 cm long wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. If the magnetic field inside the solenoid is 0.3 T, then magnetic force on the wire is

• A. 0.14 N
• B. 0.24 N
• C. 0.34 N
• D. 0.44 N

Answer 1

Answer: (B)

0.24 N

Answer 2

$\mathrm { F } = \mathrm { IlB } \sin \theta$

Here, $\theta = 90 ^ { \circ }$ ,

$\therefore \mathrm { F } = 10 \times 8 \times 10 ^ { - 2 } \times 0.3 \times \sin 90 ^ { \circ } = 0.24 \mathrm {~N}$