Question

An 120 volt ac source is connected across a pure inductor of inductance 0.70 henry. If the frequency of the source is 60 Hz, the current passing through the inductor is

• A. 4.55 amps
• B. 0.355 amps
• C. 0.455 amps
• D. 3.55 amps

Answer 1

Answer: (C)

0.455 amps

Answer 2

$i_{rms} = \frac{V_{rms}}{X_{L}} = \frac{V_{rms}}{2\pi\nu L} = \frac{120}{2\pi \times 60 \times 0.7} = 0.455A$.