Question

Amplitude of wave disturbance propagating in the positive x-axis is given by y = $\frac{1}{4(x^{2} - x + 1)}$at

t = 1 sec and by y = $\frac{1}{4(x^{2} - 3x + 4)}$at t = 3 sec, where x and y are in meters . Velocity of pulse is-

• A. 2 m/s
• B. 1.5 m/s
• C. 1 m/s
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

At = t = 1 sec : y = $\frac{1}{4(x^{2} - x + 1)}$

= $\frac{1}{(2x - 1)^{2} + 3}$

At t = 3 sec : y = $\frac{1}{4(x^{2} - 3x + 4)}$

= $\frac{1}{\{ 2(x - 1) - 1\}^{2} + 3}$

\ Wave velocity = $\frac{1m}{2\sec}$= 0.5 m/s