Solveeit Logo
Login

Question

Physics Question on Oscillations

Amplitude of a pendulum is 60 mm60 \,mm and angular velocity is 2 rad s−12 \,rad\, s^{-1}. Find its velocity if its displacement is 22 mm22 \,mm:

A

120 mm s−1120 \,mm \,s ^{-1}

B

113 mm s−1113 \,mm \,s ^{-1}

C

115 mm s−1115 \,mm \,s ^{-1}

D

125 mm s−1125 \,mm \,s ^{-1}

Answer

113 mm s−1113 \,mm \,s ^{-1}

Explanation

Solution

ω=2rad/s−1,y=20 mm\omega =2 rad / s ^{-1}, y=20\, mm, a=60 mma=60\, mm v=ωa2−y2v =\omega \sqrt{a^{2}-y^{2}} =2(60)2−(20)2=2 \sqrt{(60)^{2}-(20)^{2}} =113 mm/s−1=113\, mm / s ^{-1}