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Question: Amount of electricity that can deposit \(108g\) of silver from \(AgN{{O}_{3}}\) solution is: A. \(...

Amount of electricity that can deposit 108g108g of silver from AgNO3AgN{{O}_{3}} solution is:
A. 11 Faraday
B. 11 Ampere
C. 11 coulomb
D. None

Explanation

Solution

To find out the appropriate answer of the question given, try to state about Faraday's law and describe the two laws of Faraday. For this question, try to relate to Faraday’s second law and then you will get your correct option to choose.

Complete step by step answer:
So, before proceeding to calculation, let us know about Faraday’s law and what is electrolysis.
The process of carrying out non-spontaneous reactions under the influence of an electric energy inside an electrochemical cell is known to be electrolysis.
Michael Faraday conducted an extensive investigation on electrolysis of solutions and melts of electrolytes and he proposed two laws to explain the quantitative aspects of the electrolysis. These laws are popularly known as Faraday’s law of electrolysis.
So, coming to the second law of Faraday’s law of electrolysis, it states that “the charge of one mole of electrons is equal to one Faraday”. In short, one Faraday of charge is required to form a one-gram equivalent of an element.

Now, coming to the question given, the change in charge in the given reaction is as follows:
Ag++eAgA{{g}^{+}}+{{e}^{-}}\to Ag
We can see that; silver ions gain one electron to give one mole of silver metal weighing 108g108g.
So, as per Faraday’s law, we have to find out the gram equivalent to find out the charge which will be required to deposit 108g108g of silver.

So, Gram equivalent =Given massEquivalent wt.\text{Gram equivalent =}\dfrac{\text{Given mass}}{\text{Equivalent wt}\text{.}}
And, Equivalent wt. =Molecular massn-factor\text{Equivalent wt}\text{. =}\dfrac{\text{Molecular mass}}{\text{n-factor}}
Here, the n-factor of silver is one and molecular mass is 108g108g.
So, equivalent weight of silver is Equivalent wt. =1081=108\text{Equivalent wt}\text{. =}\dfrac{108}{1}=108
And, the gram equivalent of silver is  =108108=1\text{ =}\dfrac{108}{108}=1.
So, according to the law, if a one-gram equivalent is deposited with the requirement of one Faraday charge, then a one-gram equivalent of silver will require one Faraday charge only to get deposited.
So, the correct answer is “Option A”.

Note: Faraday was the first scientist to describe the quantitative aspects of the Laws of electrolysis. The first law states that, during electrolysis the amount of chemical reaction which occurs at any electrodes is proportional to the quantity of the electricity passed through the electrolyte.