Question

Amount of electricity required to pass through the H₂O voltameter so as to liberate 11.2 litre of hydrogen will be

• A. 1 Faraday
• B. $\frac{1}{2}Faraday$
• C. 2 Faraday
• D. 3 Faraday

Answer 1

Answer: (A)

1 Faraday

Answer 2

Mass of hydrogen in 11.2 litres of hydrogen $= \left( \frac{11.2}{22.4} \right) \times M = \left( \frac{11.2}{22.4} \right) \times 2 = 1gm$We know that 1 gm of hydrogen is equal to 1 gm equivalent wt. of hydrogen. It means that 11.2 litre of hydrogen at NTP represents 1 gm equivalent of hydrogen, so for liberation it requires 1 Faraday electricity.