Question

Amount of electricity required to liberate 16 gm of oxygen is

• A. 1 Faraday
• B. 2 Faraday
• C. $\frac{1}{2}Faraday$
• D. 3 Faraday

Answer 1

Answer: (B)

2 Faraday

Answer 2

Number of gm equivalent $= \frac{\text{Given mass }}{\text{gm equivalent weight}} = \frac{16}{16/2}$= 2. Hence 2 Faraday electricity is needed.