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Mathematics Question on mathematical reasoning

Among the statements : (S1) ((p∨q)⇒r)⇔(p⇒r)(( p \vee q ) \Rightarrow r ) \Leftrightarrow( p \Rightarrow r ) (S2) ((p∨q)⇒r)⇔((p⇒r)∨(q⇒r))(( p \vee q ) \Rightarrow r ) \Leftrightarrow(( p \Rightarrow r ) \vee( q \Rightarrow r ))

A

only (S2) is a tautology

B

both (S1) and (S2) are tautologies

C

only (S1) is a tautology

D

neither (S1) nor (S2) is a tautology

Answer

neither (S1) nor (S2) is a tautology

Explanation

Solution

neither S1 nor S2 is a tautology