Question

Among the following the dissociation constant is highest for

• A. $C _{6} H _{5} OH$
• B. $C _{6} H _{5} CH _{2} OH$
• C. $CH _{3} C \equiv CH$
• D. $CH _{3} NH _{3}{ }^{+} Cl ^{-}$

Answer 1

Answer: (D)

$CH _{3} NH _{3}{ }^{+} Cl ^{-}$

Answer 2

Among the given compounds, only $CH _{3} \overset{+}{ N}H _{3} Cl ^{-}$ is the ionic compound, hence dissociation constant is maximum for it. $CH _{3} \overset{+}{N}H _{3} Cl ^{-} \rightleftharpoons CH _{3} NH _{3}^{+}+ Cl ^{-}$ $\therefore$ dissociation constant $K=\frac{\left[ CH _{3} NH _{3}^{+}\right]\left[ Cl ^{-}\right]}{\left[ CH _{3} NH _{3}^{+} Cl ^{-}\right]}$