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Chemistry Question on Chemical bonding and molecular structure

Among the following species, identify the pair having same bond order CN−,O2−,NO+,CN+C{{N}^{-}},O_{2}^{-},N{{O}^{+}},C{{N}^{+}}

A

CN−C{{N}^{-}} and O2−O_{2}^{-}

B

O2−O_{2}^{-} and NO+N{{O}^{+}}

C

CN−C{{N}^{-}} and NO+N{{O}^{+}}

D

CN−C{{N}^{-}} and CN+C{{N}^{+}}

Answer

CN−C{{N}^{-}} and NO+N{{O}^{+}}

Explanation

Solution

Species having the same number of electrons, have same bond order.

Since, CN−C{{N}^{-}} and NO−N{{O}^{-}} have same number of electrons, they have same bond order, ie, 3.
CN−C{{N}^{-}} or NO+=14=σ1s2,σ∗1s2,σ2s2,σ∗2s2,N{{O}^{+}}=14=\sigma 1{{s}^{2}},{{\sigma }^{*}}1{{s}^{2}},\sigma 2{{s}^{2}},{{\sigma }^{*}}2{{s}^{2}},
σ2pz2,π2px2≈π2py2\sigma 2p_{z}^{2},\pi 2p_{x}^{2}\approx \pi 2p_{y}^{2}
Bond order =Nb−Na2=10−42=3=\frac{{{N}_{b}}-{{N}_{a}}}{2}=\frac{10-4}{2}=3