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Chemistry Question on Chemical bonding and molecular structure

Among the following molecules / ions, C22−,N22−,O22−,O2C^{2-}_{2}, N^{2-}_{2}, O^{2-}_{2}, O_{2} which one is diamagnetic and has the shortest bond length?

A

C22−C^{2-}_{2}

B

N22−N^{2-}_{2}

C

O2O_{2}

D

O22−O^{2-}_{2}

Answer

C22−C^{2-}_{2}

Explanation

Solution

C22− −σ1s2σ∗ 1s2σ 2s2σ∗2s2[π2px2]σ2p2C_2^{2-}\:^{-\sigma }1s^{2\sigma* }\:1s^{2\sigma }\:2s^{2\sigma* }2s^2\left[^{\pi }2p_x^2\right]^{\sigma }2p^2
B.O=10−42=3(diamagnetic)B.O=\frac{10-4}{2}=3\left(diamagnetic\right)
N22− −σ1s2σ∗ 1s2σ∗ 2s2σ2s2[π2px2=π2py2][π2px1=π∗2py1]N^{2-}_2\:^{-\sigma }1s^{2\sigma *}\:1s^{2\sigma*}\:2s^{2\sigma }2s^2\left[^{\pi 2p^2_x=^{\pi }2p^2_y}\right]\left[^{\pi }2p^1_x=^{\pi* }2p^1_y\right]
B.O=10−622(paramagnetic)B.O=\frac{10-6}{2}2\left(paramagnetic\right)
O22− −σ1s2σ1s2σ2s2σ2s2σ2pz2[π2px2=π2py2][π2px2=π∗2py2]O^{2-}_2\:^{-\sigma }1s^{2\sigma }1s^{2\sigma }2s^{2\sigma }2s^{2\sigma }2p^2_z\left[^{\pi }2p^2_x=^{\pi }2p^2_y\right]\left[^{\pi }2p^2_x=^{\pi* }2p^2_y\right]
B.O=10−82=1(diamagnetic)B.O=\frac{10-8}{2}=1\left(diamagnetic\right)
O2−σ1s2σ∗1s2σ2s2σ∗2s2σ2pz2[π2px2=π2py2][π2px1=π∗2py1]O_{2} ^{-\sigma}1s^{2\sigma*}1s^{2\sigma}2s^{2\sigma*}2s^{2\sigma}2p^{2}_{z}\left[^{\pi}2p^{2}_{x}=^{\pi}2p^{2}_{y}\right]\left[^{\pi}2p^{1}_{x}=^{\pi*}2p^{1}_{y}\right]
B.O=10−622(paramagnetic)B.O=\frac{10-6}{2}2\left(paramagnetic\right)