Question
Chemistry Question on Solutions
A
(A) (i), (ii) and (iii)
B
(B) (ii) and (iii)
C
(C) (i) and (iv)
D
(D) (ii), (iii) and (iv)
Answer
(D) (ii), (iii) and (iv)
Explanation
Solution
Explanation:
K3[Fe(CN)6]Fe+3 has 3d5 configuration, CN− is strong field ligand and thus Fe+3 has four electron paired leaving one unpaired electron with d2sp3 hybridization and thus paramagnetic.(ii) [Co(NH3)6]Cl3Co3+ has 3d6 configuration, NH3 is strong field ligands thus all six electrons are paired with d2sp3 hybridization and therefore diamagnetic.(iii) K2[Pt(CN)4]Pt+2 has 3d8 configuration, CN− is strong field ligand and thus all the eight electrons are paired with dsp2 hybridization and therefore diamagnetic.(iv) Zn(H2O)62Zn+2 has 3d10 configuration and thus all paired, showing sp3d2 hybridization and so diamagnetic.