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Question: Among KO<sub>2</sub>, \(AlO_{2}^{–}\), BaO<sub>2</sub> and \(NO_{2}^{+}\), unpaired electron is pres...

Among KO2, AlO2AlO_{2}^{–}, BaO2 and NO2+NO_{2}^{+}, unpaired electron is present in -

A

NO2+NO_{2}^{+}, BaO2

B

KO2 and AlO2AlO_{2}^{–}

C

KO2 only

D

BaO2 only

Answer

KO2 only

Explanation

Solution

KO2 is paramagnetic due to presence of unpaired electron in O2O_{2}^{–} (Super oxide).