Question
Question: Among KO<sub>2</sub>, \(AlO_{2}^{–}\), BaO<sub>2</sub> and \(NO_{2}^{+}\), unpaired electron is pres...
Among KO2, AlO2–, BaO2 and NO2+, unpaired electron is present in -
A
NO2+, BaO2
B
KO2 and AlO2–
C
KO2 only
D
BaO2 only
Answer
KO2 only
Explanation
Solution
KO2 is paramagnetic due to presence of unpaired electron in O2– (Super oxide).