Question

Among 15 players, 8 are batsmen and 7 are bowlers. Find the probability that a team is chosen of 6 batsmen and 5 bowlers

• A. $\frac { { } ^ { 8 } C _ { 6 } \times { } ^ { 7 } C _ { 5 } } { { } ^ { 15 } C _ { 11 } }$
• B. $\frac { { } ^ { 8 } C _ { 6 } + { } ^ { 7 } C _ { 5 } } { { } ^ { 15 } C _ { 11 } }$
• C. $\frac { 15 } { 28 }$
• D. None of these

Answer 1

Answer: (A)

$\frac { { } ^ { 8 } C _ { 6 } \times { } ^ { 7 } C _ { 5 } } { { } ^ { 15 } C _ { 11 } }$

Answer 2

Total number of ways $= { } ^ { 15 } C _ { 11 }$

Favourable cases $= { } ^ { 8 } C _ { 6 }$ $\times { } ^ { 7 } C _ { 5 }$

Required probability