Question

Among 100 students, $x_1$ have birthdays in January, $x_2$ have birthdays in February, and so on. If $x_0$ = $max(x_1,x_2,....,x_{12})$, then the smallest possible value of $x_0$ is

• A. 9
• B. 10
• C. 8
• D. 12

Answer 1

Answer: (A)

9

Answer 2

The correct answer is (A) : $9$

Given $x_0=(x_1,x_2,....,x_{12})$

If $x_1=x_2=x_3=x_4=9; x_5=x_6=......×12 = 8$

∴ $x_0 = max(9,9,9,9,8,8...8)$

The minimum value if $x_0$ is $9$.