Question

Ammonia is used in detection of $Cu^{2+}$ ion because

• A. aqueous solution of $NH_3$ reacts with $Cu^{2+}$ ion to form deep blue coloured complex
• B. $NH_3$ reacts with $Cu^{2+}$ ion to give blue precipitate of $CuO$
• C. aqueous solution of $NH_3$ reacts with $Cu^{2+}$ to form white coloured complex
• D. $NH_3$ reacts with $Cu^{2+}$ ion to give green precipitate

Answer 1

Answer: (A)

aqueous solution of $NH_3$ reacts with $Cu^{2+}$ ion to form deep blue coloured complex

Answer 2

${Cu^{2+}_{(aq)} +4NH3_{(aq)} ->}$ $\underset{\text{Deep blue}}{ {[Cu(NH3)4]^{2+}_{(aq)}}}$