QuestionReportQuestion: \[a^{m\log_{a}n} =\]...amlogan=a^{m\log_{a}n} =amlogan=Aamna^{mn}amnBmnm^{n}mnCnmn^{m}nmDNone of theseAnswernmn^{m}nmExplanationSolutionamlogan=aloganm=nma^{m\log_{a}n} = a^{\log_{a}n^{m}} = n^{m}amlogan=aloganm=nm.