Question
Quantitative Aptitude Question on Mixture Problems
Amar, Akbar and Anthony are working on a project. Working together Amar and Akbar can complete the project in 1 year, Akbar and Anthony can complete in 16 months,Anthony and Amar can complete in 2 years. If the person who is neither the fastest nor the slowest works alone, the time in months he will take to complete the project is
Let's denote the rates of work of Amar, Akbar, and Anthony as A, B, and C units/year, respectively.
From the given data:
1. Amar and Akbar together can complete the project in 1 year. A+B=1 (1)
2. Akbar and Anthony together can complete the project in 16 months (or 4/3 years). B+C=3/4 (2)
3. Anthony and Amar together can complete the project in 2 years. C+A=1/2 (3)
Adding all three equations, we get: 2(A + B + C) = 1 + 3/4 + 1/2 2(A + B + C) = 9/4 A + B + C = 9/8
From equation (1), we get: A = 1 - B
Plugging this into A+B+C=9/8:
1 - B + B + C = 9/8
1 + C = 9/8
C = 1/8
From equation (2):
B = 3/4 - 1/8 = 5/8
Now, let's identify the worker who is neither the fastest nor the slowest:
A = 1 - 5/8 = 3/8
B = 5/8
C = 1/8
Clearly, Akbar (B) is neither the fastest nor the slowest
If he works alone, he will take:
Time = Total work/Rate = 1 / (5/8) = 8/5 years = 19.2 months.
So, Akbar will take approximately 19.2 months to complete the project on his own