Solveeit Logo

Question

Quantitative Aptitude Question on Profit and Loss

Amal buys 110kg of syrup and 120kg of juice, syrup being 20% less costly than juice, per kg. He sells 10kg of syrup at 10% profit and 20kg of juice at 20% profit. Mixing the remaining juice and syrup, Amal sells the mixture at ₹ 308.32 per kg and makes an overall profit of 64%. Then, Amal's cost price for syrup, in rupees per kg, is

Answer

The correct answer is 160:
Step 1: Given Information
Amal purchases 110kg of syrup and 120kg of juice.
The cost price of syrup is 20% less than the cost price of juice.
Step 2: Cost Price of Syrup and Juice
Let's denote the cost price of 1 kg of juice as 10CP.
Therefore, the cost price of 1 kg of syrup is 8CP, as it is 20% less than the juice.
Step 3: Selling of Syrup and Juice
Amal sells 10kg of syrup at a 10% profit:
Selling price of 10kg syrup = 1.1×8CP=8.8CP1.1\times8CP=8.8CP
Amal sells 20kg of juice at a 20% profit:
Selling price of 20kg juice=1.2×10CP=12CP1.2\times10CP=12CP
Step 4: Selling the Mixture
Amal combines the remaining syrup and juice and sells the mixture at ₹308.32 per kg.
Total selling price of the mixture = 308.32×(110+120)=61664CP308.32\times(110 + 120) = 61664CP
Step 5: Calculating Total Cost and Profit
Total cost price=Cost price of syrup+Cost price of juice
Total cost price=110×8CP+120×10CP=2080CP110\times8CP+120\times10CP=2080CP
Overall profit = 64%
61664CP+328CP=164/100×2080CP61664CP+328CP=164/100\times2080CP
Solving for CP, we find CP = 20.
Step 6: Cost Price of Syrup
Cost price for syrup per kg = 8CP=8×20=1608CP = 8\times20 = ₹160.
Hence, the cost price for syrup is ₹160 per kg.