Question

Aluminium chloride in acidified aqueous solution forms a complex $'A'$, in which hybridisation state of $Al$ is $'B'$. What are $'A'$ and $'B'$, respectively ?

• A. $[Al(H_2O)_6]^{3+}, sp^3d^2$
• B. $[Al(H_2O)_4]^{3+}, sp^3$
• C. $[Al(H_2O)_4]^{3+}, dsp^2$
• D. $[Al(H_2O)_6]^{3+}, d^2sp^3$

Answer 1

Answer: (A)

$[Al(H_2O)_6]^{3+}, sp^3d^2$

Answer 2

$AlCl_3$ in acidified aqueous solution form a
$[Al(H_2O)_6]^{3+}$
$Al^{+3} = [Ne]$
$sp^3d^2$