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Chemistry Question on p -Block Elements

Aluminium chloride exists as dimer,Al2Cl6 { Al_2Cl_6} in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives

A

\ce[Al(OH)6]3−+3HCl\ce{[Al(OH)_6]^{3-} + 3HCl}

B

\ce[Al(H2O)6]3++3Cl−\ce{[Al(H_2O)_6]^{3+} + 3Cl^{-}}

C

\ceAl3++3Cl−\ce{Al^{3+} + 3 Cl^{-}}

D

\ceAl2O3+6HCl\ce{Al_2 O_3 + 6HCl}

Answer

\ce[Al(H2O)6]3++3Cl−\ce{[Al(H_2O)_6]^{3+} + 3Cl^{-}}

Explanation

Solution

Al2Cl6+12H2O<=>2[Al(H2O)6]3++6Cl− {Al_2Cl_6 + 12H_2O <=> 2[Al(H_2O)_6]^{3+} + 6Cl^{-}}