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Question

Mathematics Question on Functions

α=sin36\alpha = \sin 36^\circ is a root of which of the following equation?

A

16x410x25=016x^4 - 10x^2 - 5 = 0

B

16x4+20x25=016x^4 + 20x^2 - 5 = 0

C

16x420x2+5=016x^4 - 20x^2 + 5 = 0

D

16x410x2+5=016x^4 - 10x^2 + 5 = 0

Answer

16x420x2+5=016x^4 - 20x^2 + 5 = 0

Explanation

Solution

α=sin36=x(say)\alpha = \sin 36^\circ = x(say)
x=10254x = \frac{\sqrt{10} - 2\sqrt{5}}{4}
16x2=102516x^2 = 10 - 2\sqrt{5}
(8x25)2=5(8x^2 - 5)^2 = 5
16x480x2+20=016x^4 - 80x^2 + 20 = 0
4x420x2+5=04x^4 - 20x^2 + 5 = 0