Question

All resistances in figure are 1 Ω each. The value of current ‘I‘ is $(\frac{a}{5})$ A. The value of a is _______.

Answer 1

Let the current is i
Using kirchhoff’s law
$iR+\frac{i}{2R}+\frac{i}{4R}+\frac{i}{8R}=3$
$i=\frac{3×8}{15}=\frac{8}{5} A$

Since,$I=(\frac{a}{5})A$
$⇒ a=8$
So, value of a is 8