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Question: All of the following can act as Bronsted- Lowry acids (proton donors) in aqueous solution except : ...

All of the following can act as Bronsted- Lowry acids (proton donors) in aqueous solution except :
A.HIHI
B.NH4+N{H_4}^ +
C.HCO3HC{O_3}^ -
D.H2S{H_2}S
E.NH3N{H_3}

Explanation

Solution

A bronsted lowry acid is any species that's capable of giving up or donating one or more hydrogen ions during a chemical action. Every bronsted lowry acid donates its proton to a species which is usually its conjugate base.

Complete step by step answer:
-A Brønsted-Lowry acid may be a proton (hydrogen ion), donor.
-A Brønsted-Lowry base could be a proton (hydrogen ion), the acceptor.
-In this theory, an acid could be a substance which will release a proton (like within the Arrhenius theory) and a base may be a substance which will accept a proton. When a Brønsted acid dissociates, it increases the concentration of hydrogen ions [H+]\left[ {{H^ + }} \right]within the solution, conversely, Brønsted bases dissociate by taking a proton from the solvent (water) to come up with hydroxide ions [OH]\left[ {O{H^ - }} \right] within the solution.
Acid dissociation:
HAA+H(aq)+HA\underset {} \leftrightarrows {A^ - } + {H_{(aq)}}^ +
Base dissociation:
B(aq)+H2OHB++OH(aq){B_{(aq)}} + {H_2}O\underset {} \leftrightarrows H{B^ + } + O{H^ - }_{(aq)}^{}
A.HIHI dissociates to form H3O+{H_3}{O^ + } ions in the solution hence it is a Brønsted-Lowry acid.
B.NH4++H2OH3O++NH3NH_4^ + + {H_2}O\underset {} \leftrightarrows {H_3}{O^ + } + N{H_3}
Ammonium ion dissociates to give H+{H^ + }ions in the solution hence it is a Brønsted-Lowry acid.
C.HCO3HC{O_3}^ - is the conjugate base of carbonic acid and the conjugate acid of the carbonate ion. Hence it can act as both acid and base.
D. H2S{H_2}S +H2OH3O++SH + {H_2}O\underset {} \leftrightarrows {H_3}{O^+ } + S{H^-}
H2S{H_{2}S} is a Bronsted-Lowry acid because it is donating a proton to water.
E. NH3+H2ONH4++OHN{H_3} + {H_2}O \to NH_4^+ + O{H^ - }
Since Ammonia is accepting a proton from H2O{H_2}O, it is behaving like a Brønsted-Lowry base.
Thus the correct option is E.

Note:
-When a Bronsted-Lowry acid donates a proton to a different compound, the particle that's missing the proton becomes its conjugate base. Together they're called a conjugate acid-base pair.
-When an acid HAHA dissolves in water, it reacts reversibly with the water to supply hydronium ions and A{A^ - } ions.
HA+H2OH3O+AHA + {H_2}O\underset {} \leftrightarrows {H_3}O + {A^ - }
-In this, HAHA has donated a proton to water thus HA is the Bronsted-Lowry
acid and water is the Bronsted-Lowry base.
-A conjugate base is whatever is left behind after the proton has left. So A{A^ - } is the conjugate base of HAHA
-A conjugate acid is whatever is formed after the proton has been accepted. So, H3O+{H_3}{O^ + } is the conjugate acid of water.