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Question: Alkene (X) \(\left( \mathrm { C } _ { 5 } \mathrm { H } _ { 10 } \right)\)on ozonolysis gives a mixt...

Alkene (X) (C5H10)\left( \mathrm { C } _ { 5 } \mathrm { H } _ { 10 } \right)on ozonolysis gives a mixture of two compounds (Y) and (Z). Compound (Y) gives positive Fehling’s test and iodoform test. Compound (Z) does not give Fehling’s test but give iodoform test. Compounds (X), (Y) and (Z) are

X Y Z

A

CH3CHO\mathrm { CH } _ { 3 } \mathrm { CHO } CH3COCH3\mathrm { CH } _ { 3 } \mathrm { COCH } _ { 3 }

B

CH3COCH3\mathrm { CH } _ { 3 } \mathrm { COCH } _ { 3 }

C

CH3CH2CH=CH2\mathrm { CH } _ { 3 } \mathrm { CH } _ { 2 } \mathrm { CH } = \mathrm { CH } _ { 2 } CH3CH2CHO\mathrm { CH } _ { 3 } \mathrm { CH } _ { 2 } \mathrm { CHO } HCHO

D

CH3CH=CHCH3\mathrm { CH } _ { 3 } - \mathrm { CH } = \mathrm { CH } - \mathrm { CH } _ { 3 } CH3CHO\mathrm { CH } _ { 3 } \mathrm { CHO } CH3CHO\mathrm { CH } _ { 3 } \mathrm { CHO }

Answer

CH3COCH3\mathrm { CH } _ { 3 } \mathrm { COCH } _ { 3 }

Explanation

Solution

: \mathrm { CH } _ { 3 } - \mathrm { CH } = \underset { \substack { 1 \\ \mathrm { CH } _ { 3 } } } { \mathrm { C } } - \mathrm { CH } _ { 3 } \xrightarrow \left[ \left( \text { (ii) } \mathrm { Zn } / \mathrm { H } _ { 2 } \mathrm { O } \right] { ( \text { (i) } } \right.