Question

Alkanes have the general molecular formula ${C_n}{H_{2n + 2}}$. Thus, when n= $1$, the alkane is $C{H_4}$, when n=$2$ , the alkane is ${C_2}{H_6}$ etc. If an alkane has a molar mass between $140{\text{ }}\& {\text{ }}150$, what is the alkane?

Answer 1

In natural chemistry, an alkane is an acyclic saturated hydrocarbon. In different words, an alkane includes hydrogen and carbon atoms organized in a tree shape wherein all of the carbon-carbon bonds are unmarried. Alkanes have the overall chemical method.

Complete answer:
This is an easy calculation.
The widespread method for alkanes is ${C_n}{H_{2n + 2}}$ .
So, an alkane having $10$ carbon atoms will actually have $22$ hydrogen atoms, consistent with the given method. So, the molar mass of decane is the same to:

$$= (10 \times 12) + (22 \times 1)\;grams \\\ = 142\;grams \\\$$

So, the alkane is Decane.
Alkanes with greater than $3$ carbon atoms may be organized in numerous ways, forming structural isomers. The most effective isomer of an alkane is the only wherein the carbon atoms are organized in an unmarried chain and not using a branch. This isomer is once in a while known as the n-isomer (n for "normal", even though it isn't always the maximum common). However, the chain of carbon atoms will also be branched at one or greater points. An alkene is a hydrocarbon having a carbon-carbon double bond in Chemistry. Alkene is regularly used as a synonym of olefin, that is, any hydrocarbon containing one or greater double bonds. Two widespread sorts of mono alkenes are distinguished: terminal and internal. Also known as α-olefins, terminal alkenes are more useful.

Note:
However, the IUPAC recommends using the name "alkene" handiest for acyclic hydrocarbons with simply one double bond; alkadiene, alkatriene, etc., or polyene for acyclic hydrocarbons with or greater double bonds; cycloalkene, cycloalkadiene, etc. for cyclic ones; and "olefin" for the overall class — cyclic or acyclic, with one or greater double bonds.