Question

$AlCl_{3}$ achieves stability by forming a dimer. In trivalent state the compound is hydrolysed in water. $AlCl_{3}$ in acidified aqueous solution forms.

• A. $Al(OH)_{3} + HCl$
• B. $\lbrack Al\left( H_{2}O \right)_{6}\rbrack^{3 +} + 3Cl^{-}$
• C. $AlCl_{3}2H_{2}O$
• D. $Al_{2}O_{3} + HCl$

Answer 1

Answer: (B)

$\lbrack Al\left( H_{2}O \right)_{6}\rbrack^{3 +} + 3Cl^{-}$

Answer 2

: $AlCl_{3}$ in acidified aqueous solution forms $\lbrack Al(H_{2}O)_{6}\rbrack^{3 +}$ ion.

$AlCl_{3} + 9H_{2}O \rightarrow \lbrack Al(H_{2}O)_{6}\rbrack(OH)_{3} + 3H^{+} + 3Cl^{-}$