( {AlCl3}) on hydrolysis gives | Chemistry | SolveeIt

${AlCl3}$ on hydrolysis gives

$\ce{Al2O3. H2O }$

$\ce{Al(OH)3 }$

$\ce{ Al2O3 }$

$\ce{AlCl3 .6H2O }$

Answer

$\ce{Al(OH)3 }$

Explanation

$AlCl _{3}$ on hydrolysis gives $Al ( OH )_{3}$ Hydrolysis is breaking with the help of water. $AlCl _{3}+3 H _{2} O \rightarrow Al ( OH )_{3}+3 HCl$

Chemistry Question on p -Block Elements