Question

$aK _{2} Cr _{2} O _{7}+ bKCl + cH _{2} SO _{4} \longrightarrow xCrO _{2} Cl _{2}+ yKHSO _{4}+ zH _{2} O$ The above equation balances when

• A. a = 2, b = 4, c = 6 and x = 2, y = 6, z = 3
• B. a = 4, b = 2, c = 6 and x = 6, y = 2, z = 3
• C. a = 6, b = 4, c = 2 and x = 6, y = 3, z = 2
• D. a = 1, b = 4, c = 6 and x = 2, y = 6, z = 3

Answer 1

Answer: (D)

a = 1, b = 4, c = 6 and x = 2, y = 6, z = 3

Answer 2

Here, $K _{2} Cr _{2} O _{7}$ acts as a oxidizing agent.
Basically, Hydrogen and oxygen atoms are balanced on both sides of the equation.
The balanced equation is :
$K _{2} Cr _{2} O _{7}+4 KCl +6 H _{2} SO _{4}=2 CrO _{2} Cl _{2}+6 KHSO _{4}+3 H _{2} O$
It is a redox reaction. After complete balance equation, the values of variables are:
$a=1, b=4, c=6, x=2, y=6, z=3$.